5j^2-134=162

Solution for 5j^2-134=162 equation:

5j^2-134=162

We move all terms to the left:

5j^2-134-(162)=0

We add all the numbers together, and all the variables

5j^2-296=0

a = 5; b = 0; c = -296;
Δ = b2-4ac
Δ = 02-4·5·(-296)
Δ = 5920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5920}=\sqrt{16*370}=\sqrt{16}*\sqrt{370}=4\sqrt{370}$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{370}}{2*5}=\frac{0-4\sqrt{370}}{10}
=-\frac{4\sqrt{370}}{10}
=-\frac{2\sqrt{370}}{5}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{370}}{2*5}=\frac{0+4\sqrt{370}}{10}
=\frac{4\sqrt{370}}{10}
=\frac{2\sqrt{370}}{5}
$